7
algebra

A father is 30 years older than his son. In 10 years, he will be twice as old as his son. How old is the son now?

A

10

B

30

C

50

D

20

Correct Answer: D

Choice Ahoice B is the correct answer.

  1. Define: Son = xx, Father = x+30x + 30.
  2. In 10 years: Son = x+10x+10, Father = x+40x+40.
  3. Equation: x+40=2(x+10)x + 40 = 2(x + 10)
  4. Solve: x+40=2x+2020=xx + 40 = 2x + 20 \rightarrow 20 = x
  5. Verify: Son 20, Father 50. In 10 years: 30, 60. 60=2(30)60 = 2(30)

Choice Ahoice C is incorrect because this is the father's age.

Choice Ahoice D is incorrect because calculation error.

Choice Ahoice D is incorrect because calculation error.