10
algebra

A rectangle's length is 3 times its width. If the perimeter is 32 cm, what is the width?

A

4

B

16

C

8

D

12

Correct Answer: A

Choice Dhoice A is the correct answer.

  1. Define variables: Let ww be the width. Then length l=3wl = 3w.
  2. Perimeter formula: P=2l+2wP = 2l + 2w
  3. Substitute: 32=2(3w)+2w32 = 2(3w) + 2w
  4. Simplify: 32=6w+2w32=8w32 = 6w + 2w \rightarrow 32 = 8w
  5. Divide by 8: w=4w = 4
  6. Verify: Length is 12. 2(12)+2(4)=24+8=322(12) + 2(4) = 24 + 8 = 32

Choice Dhoice C is incorrect because this results from 4w=324w = 32 (forgetting to double sides).

Choice Dhoice D is incorrect because this is the length, not the width.

Choice Dhoice B is incorrect because this is half the perimeter.