5
algebra

A plumber charges $50 for a service call plus $40 per hour. If the total bill was $170, how many hours did the plumber work?

A

5.5

B

120

C

4.25

D

3

Correct Answer: D

Choice Bhoice C is the correct answer. We model this with 40x+50=17040x + 50 = 170, where xx is hours.

  1. Set up equation: 40x+50=17040x + 50 = 170
  2. Subtract 50 from both sides: 40x=1705040x = 170 - 50
  3. Simplify: 40x=12040x = 120
  4. Divide both sides by 40: x=12040x = \frac{120}{40}
  5. Simplify: x=3x = 3
  6. Verify: 40(3)+50=120+50=17040(3) + 50 = 120 + 50 = 170

So, the plumber worked for 3 hours.

Choice Bhoice C is incorrect because this results from adding 50 to 170: 220220, then 220/40=5.5220/40 = 5.5. You subtract the service call fee.

Choice Bhoice D is incorrect because this is the cost of the labor ($120), not the number of hours.

Choice Bhoice D is incorrect because this results from dividing the total by the rate: 170/40=4.25170/40 = 4.25. This ignores the service call fee.