9
advanced-math

Solve for xx: 2x+3=x\sqrt{2x + 3} = x.

A

3

B

3, -1

C

-1

D

No solution

Correct Answer: A

Choice A is the correct answer.

  1. Square both sides: 2x+3=x22x + 3 = x^2.
  2. Rearrange: x22x3=0x^2 - 2x - 3 = 0.
  3. Factor: (x3)(x+1)=0(x - 3)(x + 1) = 0.
  4. Potential roots: 3,13, -1.
  5. Check: 2(3)+3=9=3\sqrt{2(3)+3} = \sqrt{9} = 3 (Matches x). 2(1)+3=1=1eq1\sqrt{2(-1)+3} = \sqrt{1} = 1 eq -1. So -1 is extraneous.

Choice B is incorrect because -1 is extraneous. Choice C is incorrect. Choice D is incorrect.