3
advanced-math

The stopping distance dd (in feet) of a car is modeled by d(v)=0.05v2+vd(v) = 0.05v^2 + v, where vv is speed in mph. What is the stopping distance at 60 mph?

A

240 ft

B

180 ft

C

300 ft

D

120 ft

Correct Answer: A

Choice A is the correct answer. Substitute v=60v=60 into the model.

  1. d(60)=0.05(60)2+60d(60) = 0.05(60)^2 + 60.
  2. d(60)=0.05(3600)+60d(60) = 0.05(3600) + 60.
  3. d(60)=180+60=240d(60) = 180 + 60 = 240 feet.

Choice B is incorrect. Choice C is incorrect. Choice D is incorrect.

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Set 19: Quadratic Equations and Functions 19