8
advanced-math

What is the minimum cost for C(x)=x2−10x+40C(x) = x^2 - 10x + 40?

A

15

B

5

C

40

D

25

Correct Answer: A

Choice A is the correct answer.

  1. Vertex x: x=−(−10)/2=5x = -(-10)/2 = 5.
  2. Minimum Cost: Substitute x=5x=5. C(5)=52−10(5)+40C(5) = 5^2 - 10(5) + 40C(5)=25−50+40=15C(5) = 25 - 50 + 40 = 15.

Choice B is incorrect because it is the x-value. Choice C is incorrect because it is the y-intercept. Choice D is incorrect.

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Set 18: Quadratic Equations and Functions 18