6
advanced-math

The product of two consecutive positive even integers is 168. Find the integers.

A

12 and 14

B

10 and 12

C

14 and 16

D

8 and 10

Correct Answer: A

Choice A is the correct answer.

  1. Setup: Let integers be xx and x+2x+2.
  2. Equation: x(x+2)=168x2+2x168=0x(x+2) = 168 \Rightarrow x^2 + 2x - 168 = 0.
  3. Factor: (x+14)(x12)=0(x + 14)(x - 12) = 0.
  4. Result: x=12x = 12 (since positive). Next integer is 14.

Choice B is incorrect because product is 120. Choice C is incorrect because product is 224. Choice D is incorrect because product is 80.