8
advanced-math

How many points of intersection between y=x2y = x^2 and x=y2x = y^2?

A

2

B

1

C

4

D

0

Correct Answer: A

Choice A is the correct answer.

  1. Substitute y=x2y=x^2 into x=y2x=y^2: x=(x2)2=x4x = (x^2)^2 = x^4.
  2. x4x=0x^4 - x = 0.
  3. Factor: x(x31)=0x(x^3 - 1) = 0.
  4. Real solutions: x=0x = 0 and x=1x = 1.
  5. Points: (0,0)(0,0) and (1,1)(1,1).

Choice B is incorrect. Choice C is incorrect. Choice D is incorrect.