7
advanced-math

Solve: 2x282x^2 \geq 8

A

x2x \geq 2 or x2x \leq -2

B

2x2-2 \leq x \leq 2

C

x4x \geq 4

D

x2x \geq 2

Correct Answer: A

Choice A is the correct answer.

  1. Divide by 2: x24x^2 \geq 4.
  2. Square root property: x2|x| \geq 2.
  3. This splits into two cases: x2x \geq 2 or x2x \leq -2.

Choice B is incorrect because that is for x24x^2 \leq 4. Choice C is incorrect. Choice D is incorrect because it misses the negative part.