6
advanced-math

What is the solution set for x2<4x^2 < -4?

A

Empty set (No solution)

B

All real numbers

C

x<2x < -2

D

2<x<2-2 < x < 2

Correct Answer: A

Choice A is the correct answer.

  1. x2x^2 must be non-negative (x20x^2 \geq 0).
  2. It is impossible for a non-negative number to be less than a negative number (-4).
  3. Therefore, there is no solution.

Choice B is incorrect. Choice C is incorrect. Choice D is incorrect.