3
advanced-math

Find a quadratic equation with roots 3 and -5.

A

x2+2x15=0x^2 + 2x - 15 = 0

B

x22x15=0x^2 - 2x - 15 = 0

C

x2+2x+15=0x^2 + 2x + 15 = 0

D

x215x+2=0x^2 - 15x + 2 = 0

Correct Answer: A

Choice A is the correct answer.

Method 1: Factoring If roots are 3 and -5, factors are (x3)(x - 3) and (x+5)(x + 5). Multiply: (x3)(x+5)=x2+5x3x15=x2+2x15(x - 3)(x + 5) = x^2 + 5x - 3x - 15 = x^2 + 2x - 15.

Method 2: Vieta's Formulas Sum = 3+(5)=23 + (-5) = -2. Product = 3(5)=153(-5) = -15. Equation: x2(Sum)x+Product=0x2(2)x15=0x2+2x15=0x^2 - (Sum)x + Product = 0 \Rightarrow x^2 - (-2)x - 15 = 0 \Rightarrow x^2 + 2x - 15 = 0.

Choice B is incorrect because sum is -2, so coefficient should be +2. Choice C is incorrect because product is -15. Choice D is incorrect because it swaps sum and product.