8
advanced-math

A student solved 2x24x3=02x^2 - 4x - 3 = 0 and got x=4±402x = \frac{4 \pm \sqrt{40}}{2}. What error did they make?

A

Wrong denominator

B

Wrong sign for b

C

Wrong discriminant calculation

D

No error

Correct Answer: A

Choice A is the correct answer. The quadratic formula is x=b±Δ2ax = \frac{-b \pm \sqrt{\Delta}}{2a}.

  • Here a=2a=2, so the denominator should be 2(2)=42(2) = 4.
  • The student used 2, likely forgetting to multiply by aa.

Choice B is incorrect because (4)=4-(-4) = 4 is correct. Choice C is incorrect because Δ=(4)24(2)(3)=16+24=40\Delta = (-4)^2 - 4(2)(-3) = 16 + 24 = 40 is correct. Choice D is incorrect because the denominator is definitely wrong.