5
advanced-math

Solve: 3(x2)2=123(x - 2)^2 = 12

A

x=4,0x = 4, 0

B

x=6,2x = 6, -2

C

x=4,4x = 4, -4

D

x=2±12x = 2 \pm \sqrt{12}

Correct Answer: A

Choice A is the correct answer.

  1. Isolate the squared term by dividing by 3: (x2)2=4(x - 2)^2 = 4.
  2. Take the square root: x2=±2x - 2 = \pm 2.
  3. Solve for x:
    • x=2+2=4x = 2 + 2 = 4
    • x=22=0x = 2 - 2 = 0

Choice B is incorrect because it likely solved (x2)2=16(x-2)^2=16 (multiplied by 3 instead of dividing? No, 1616 comes from 12+412+4? Unclear logic, but wrong). Choice C is incorrect because it forgets to add 2 to the solutions. Choice D is incorrect because it forgets to divide by 3 first.