10
advanced-math

The area of a rectangular garden is given by A=x2+5x+6A = x^2 + 5x + 6. If the width is (x+2)(x + 2), what is the length?

A

(x+3)(x + 3)

B

(x+4)(x + 4)

C

(x+2)(x + 2)

D

(x+1)(x + 1)

Correct Answer: A

Choice A is the correct answer. The area of a rectangle is Area=Length×Width\text{Area} = \text{Length} \times \text{Width}.

  1. We are given Area =x2+5x+6= x^2 + 5x + 6 and Width =(x+2)= (x + 2).
  2. We need to find the other factor of the quadratic.
  3. Factor x2+5x+6x^2 + 5x + 6: We need numbers that multiply to 6 and add to 5. They are 2 and 3.
  4. So, x2+5x+6=(x+2)(x+3)x^2 + 5x + 6 = (x + 2)(x + 3).

Since the width is (x+2)(x + 2), the length must be (x+3)(x + 3).

Choice B is incorrect because (x+2)(x+4)=x2+6x+8(x+2)(x+4) = x^2 + 6x + 8. Choice C is incorrect because (x+2)(x+2)=x2+4x+4(x+2)(x+2) = x^2 + 4x + 4. Choice D is incorrect because (x+2)(x+1)=x2+3x+2(x+2)(x+1) = x^2 + 3x + 2.