Choice B is the correct answer. This quadratic is a Perfect Square Trinomial.

1. Notice that half of 8 is 4, and $4^2 = 16$.
2. This fits the pattern $(a+b)^2 = a^2 + 2ab + b^2$.
3. Factor as $(x + 4)^2 = 0$.
4. Take the square root: $x + 4 = 0 \Rightarrow x = -4$.

Since the factor is squared, -4 is a "repeated root" (multiplicity 2).

Choice A is incorrect because of a sign error. Choice C is incorrect because a perfect square equal to zero has only one distinct solution. Choice D is incorrect because these values do not satisfy the equation.