5
advanced-math

Factor completely: 2x2+6x2x^2 + 6x

A

2x(x+3)2x(x + 3)

B

x(2x+6)x(2x + 6)

C

2(x2+3x)2(x^2 + 3x)

D

2x(x3)2x(x - 3)

Correct Answer: A

Choice A is the correct answer. To factor completely, always look for a Greatest Common Factor (GCF) first.

  1. The coefficients are 2 and 6. The GCF is 2.
  2. The variables are x2x^2 and xx. The GCF is xx.
  3. Combine them: The total GCF is 2x2x.
  4. Divide each term by 2x2x: 2x2/2x=x2x^2/2x = x and 6x/2x=36x/2x = 3.

So, the factored form is 2x(x+3)2x(x + 3).

Choice B is incorrect because 2x+62x+6 can still be factored further (divisible by 2). Choice C is incorrect because it leaves an xx inside that could be factored out. Choice D is incorrect because expanding 2x(x3)2x(x-3) gives 2x26x2x^2 - 6x, which has the wrong sign.