Choice A is the correct answer. Evaluate at $t = 10$.

1. Substitute: $T(10) = 70 + 130e^{-0.1(10)} = 70 + 130e^{-1}$.
2. Calculate: $e^{-1} = \frac{1}{e} \approx 0.3679$.
3. Compute: $130(0.3679) \approx 47.83$.
4. Result: $T(10) = 70 + 47.83 \approx 118°F$.

💡 Strategic Tip: Newton's Law: $T(t) = T_{\text{room}} + (T_0 - T_{\text{room}})e^{-kt}$.

Choice B is incorrect because this doesn't account for exponential decay. Choice C is incorrect because it hasn't cooled to room temperature yet. Choice D is incorrect because the decay is not that rapid.