Choice A is the correct answer. Use the shifted exponential model.

1. Model: $T(t) = (T_0 - T_{\text{room}})(b)^t + T_{\text{room}}$.
2. Given: $T_0 = 95$, $b = 0.9$, $T(10) = 59.38$.
3. Set up: $59.38 = (95 - T_{\text{room}})(0.9)^{10} + T_{\text{room}}$.
4. Solve: $(0.9)^{10} \approx 0.3487$, so: $59.38 = (95 - T_{\text{room}})(0.3487) + T_{\text{room}}$$59.38 = 33.13 - 0.3487T_{\text{room}} + T_{\text{room}}$$26.25 \approx 0.6513T_{\text{room}}$$T_{\text{room}} \approx 20°\text{C}$

💡 Strategic Tip: The horizontal asymptote represents room temperature in cooling problems.

Choice B is incorrect because room temperature isn't freezing. Choice C is incorrect because this doesn't match the calculation. Choice D is incorrect because this is too warm.