Choice A is the correct answer. Analyze the function's behavior.

1. Base: $0.6 < 1$ means decay.
2. As $x \to \infty$: $(0.6)^x \to 0$, so $h(x) \to 0 + 5 = 5$ (approaches from above).
3. As $x \to -\infty$: $(0.6)^x \to \infty$, so $h(x) \to \infty$.
4. Range: $y > 5$ (never reaches 5, asymptote).

💡 Strategic Tip: The range is bounded by the horizontal asymptote.

Choice B is incorrect because the function stays above the asymptote. Choice C is incorrect because 12 is the coefficient, not a bound. Choice D is incorrect because there's a lower bound at $y = 5$.