Set 7: Systems of Equations (Intermediate)

Choice B is correct. Choice B is the correct answer. Multiply second by 3 to eliminate $y$. Step 1: Multiply second by 3: $6x - 3 y = 15$ Step 2: Add to first: (5 x + 3 y) + (6 x - 3 y) = 28 + 15$11x = 43$x = \frac{43}{11} Non-integer. - First: $5(5) + 3(1) = 25 + 3 = 28$ ✓ - Second: $2(5) - 1 = 10 - 1 = 9 \neq 5$ Strategic Tip: Multiplying by 3 creates $-3 y$ to cancel $+3 y$. Other choices fail verification.