Set 6: Systems of Equations (Advanced)

Choice C is correct. Choice C is the correct answer. Let $a$ be the number of adult tickets and $c$ be the number of child tickets. Given: $a = 2$ and $8a + 5 c = 41$ Step 1: Substitute $a = 2$: 8(2) + 5 c = 41$16+ 5 c = 41$$$ Step 2: Solve for $c$: $$$5c = 25$c = 5 Solution: They bought 5 child tickets. Verification: $8(2) + 5(5) = 16 + 25 = 41$ ✓ Strategic Tip: When one value is given, substitute it immediately to simplify the problem. Choice A is incorrect because $8(2) + 5(4) = 16 + 20 = 36 \neq 41$. Choice B is incorrect because $8(2) + 5(6) = 16 + 30 = 46 \neq 41$. Choice D is incorrect because $8(2) + 5(3) = 16 + 15 = 31 \neq 41$.