Set 17: Quadratic Equations (Intermediate)

Choice A is correct. Choice A is the correct answer. You can solve this by factoring or using square roots. Method 1 (Factoring): 1. Recognize difference of squares: $(2 x)^2 - 3^2 = 0$. 2. Factor: $(2 x - 3)(2 x + 3) = 0$. 3. Solve: $2x = 3 \Rightarrow x = 3/2$ and $2x = -3 \Rightarrow x = -3/2$. Method 2 (Square Roots): 1. Isolate $x^2$: $4x^2 = 9 \Rightarrow x^2 = 9/4$. 2. Take square root: $x = \pm \sqrt{9/4} = \pm 3/2$. Choice B is incorrect because it forgets to take the square root. Choice C is incorrect because it misses the negative solution. Choice D is incorrect because the fraction is inverted (should be $\sqrt{9}/\sqrt{4}$).