Set 10: Quadratic Equations (Intermediate)

Explanation

Answer: A

Solve the system: $y = -x^2 + 4$ and $y = 0$ .

$(\pm 2, 0)$

✓ Correct

$(4, 0)$

$(0, 4)$

$(\pm 4, 0)$

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Solving for intersection with $y=0$ is equivalent to finding the x-intercepts. 1. $-x^2 + 4 = 0$ . 2. $x^2 = 4$ . 3. $x = \pm 2$ . 4. Points: $(2, 0)$ and $(-2, 0)$ . Choice B is incorrect. Choice C is incorrect because it is the y-intercept. Choice D is incorrect.

Key Steps:

•

The correct answer is $(\pm 2, 0)$

Why others are wrong:

B: Choice B is incorrect and may result from a calculation error.

C: Choice C is incorrect and may result from a calculation error.

D: Choice D is incorrect and may result from a calculation error.

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