Set 11: Quadratic Equations

Choice B is correct. Choice B is the correct answer. 1. Take the square root of both sides: $\sqrt{(x+4)^2} = \sqrt{0}$. 2. Simplify: $x + 4 = 0$. 3. Solve: $x = -4$. Since 0 has only one square root (0), there is only one unique solution (a repeated root). Choice A is incorrect because of a sign error. Choice C is incorrect because 0 does not have a negative square root. Choice D is incorrect because it sets $x=0$ instead of the expression.