Set 15: Quadratic Equations (Advanced)

Choice A is correct. Choice A is the correct answer. To solve $(x - 2)^2 = 9$, use the Square Root Property. 1. Take the square root of both sides: $\sqrt{(x-2)^2} = \pm\sqrt{9}$. 2. Simplify: $x - 2 = \pm 3$. 3. Set up two equations: * $x - 2 = 3 \Rightarrow x = 5$ * $x - 2 = -3 \Rightarrow x = -1$ Choice B is incorrect because it squares 3 instead of taking the root ($x-2 = \pm 9$). Choice C is incorrect because $x-2=-3$ gives $-1$, not $1$ (sign error). Choice D is incorrect because it forgets to add 2 to the solutions.