6

Set 13: Linear Inequalities (Intermediate)

Explanation

Answer: A

Which is the solution to 3(x+2)12-3(x + 2) \geq 12?

A.

x6x \leq -6

✓ Correct
B.

x6x \geq -6

C.

x2x \leq -2

D.

x2x \geq -2

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Distributing a negative coefficient creates a negative variable term. 1. Distribute: 3(x)+(3)(2)12-3(x) + (-3)(2) \geq 12, giving 3x612-3 x - 6 \geq 12 2. Add 6: 3x18-3 x \geq 18 3. Divide by -3: x6x \leq -6 (REVERSE the sign!) Strategic Tip: When dividing by a negative number, always flip the inequality direction. Choice B is incorrect because it fails to reverse the inequality when dividing by -3. Choice C is incorrect because it uses -2 instead of -6, possibly from incorrect arithmetic. Choice D is incorrect because it combines the wrong value with failure to reverse the sign.

Key Steps:

The correct answer is x6x \leq -6

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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