Set 12: Linear Inequalities (Intermediate)

Choice A is correct. Choice A is the correct answer. Solve each part. 1. Part 1: $-x < -3 \rightarrow x > 3$ (Reverse!) 2. Part 2: $-x > 3 \rightarrow x < -3$ (Reverse!) 3. Combine: $x > 3$ or $x < -3$ Strategic Tip: Dividing by -1 reverses inequality signs in both cases. Choice B is incorrect because it fails to reverse signs. Choice C is incorrect because it combines incorrectly. Choice D is incorrect because it tries to form an "and" interval.