Set 12: Linear Inequalities

Choice A is correct. Choice A is the correct answer. Real-world pricing problems often combine fixed and variable costs. 1. Fixed cost: First hour costs $62. Variable cost: Each additional hour costs \4, so additional hours cost 4 h$$ 3. Total: $$6+ 4 h$$ 4. Constraint: "Has \30" means total $\leq 30$: $4h + 6 \leq 30$ Strategic Tip: Identify fixed costs (constant) vs variable costs (coefficient times variable) when setting up inequalities. Choice B is incorrect because it reverses the costs, making $6the per-hour rate and \4 the initial fee. Choice C is incorrect because it subtracts the fixed cost, which doesn't match the pricing adding structure. Choice D is incorrect because it adds the costs (6+4=10) and multiplies by $$h$, incorrectly treating both as variable.