Set 12: Linear Inequalities

Choice A is correct. Choice A is the correct answer. Isolate $x$ and reverse signs. 1. Subtract 3: $-8 < -2 x \leq 6$ 2. Divide by -2: $4> x \geq -3$ (Reverse signs!) 3. Rewrite: $-3 \leq x < 4$ Strategic Tip: When rewriting $4> x \geq -3$, start with the smallest number: $-3 \leq x < 4$. Choice B is incorrect because it swaps the strict/inclusive endpoints. Choice C is incorrect because it calculates endpoints incorrectly. Choice D is incorrect because it writes the interval backwards ($4< -3$ is impossible).