6

Set 17: Linear Inequalities (Advanced)

Explanation

Answer: A

If x2+x3>10\frac{x}{2} + \frac{x}{3} > 10, what is the solution?

A.

x>12x > 12

✓ Correct
B.

x>6x > 6

C.

x>60x > 60

D.

x>5x > 5

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Combine fractions using a common denominator. 1. LCD of 2 and 3 is 6: Multiply all terms by 6. 2. Multiply: 6(x2)+6(x3)>6(10)6(\frac{x}{2}) + 6(\frac{x}{3}) > 6(10) 3. Simplify: 3x+2x>603x + 2 x > 60 4. Combine: 5x>605x > 60 5. Divide by 5: x>12x > 12 Strategic Tip: Alternatively, x2+x3=3x6+2x6=5x6\frac{x}{2} + \frac{x}{3} = \frac{3 x}{6} + \frac{2 x}{6} = \frac{5 x}{6}. Then 5x6>105x>60x>12\frac{5 x}{6} > 10 \rightarrow 5 x > 60 \rightarrow x > 12. Choice B is incorrect because it might come from adding denominators (2+3=52 +3=5) incorrectly. Choice C is incorrect because it forgets to divide by 5. Choice D is incorrect because it divides 60 by 12 or similar error.

Key Steps:

The correct answer is x>12x > 12

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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