Set 15: Linear Inequalities (Advanced)

Choice A is correct. Choice A is the correct answer. Set up the inequality and solve for the integer constraint. 1. Setup: $8.99+ 4.99 p \leq 25$ 2. Subtract 8.99: $4.99p \leq 16.01$ 3. Divide by 4.99: $p \leq 3.21...$ 4. Integer constraint: Since $p$ must be whole, maximum is $p = 3$ Strategic Tip: Real-world quantities often require integer solutions, so round down for maximums. Choice B is incorrect because $p = 4$ would cost $8.99+ 4(4.99) = 28.95$, exceeding $25. Choice C is incorrect because it excludes $p = 3$, which does work ($8.99+ 3(4.99) = 23.96 < 25$). Choice D is incorrect because while $p < 4$ is technically true, $p \leq 3$ is more precise for integers.