10

Set 13: Linear Inequalities (Advanced)

Explanation

Answer: A

Solve: 3<2x+17-3 < 2x + 1 \leq 7

A.

2<x3-2 < x \leq 3

✓ Correct
B.

2x<3-2 \leq x < 3

C.

1<x4-1 < x \leq 4

D.

1x<4-1 \leq x < 4

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Solve the compound inequality by performing operations on all three parts simultaneously. 1. Subtract 1: 31<2x+1171-3 - 1 < 2 x + 1 - 1 \leq 7 - 1, giving 4<2x6-4 < 2 x \leq 6 2. Divide by 2: 42<2x262\frac{-4}{2} < \frac{2 x}{2} \leq \frac{6}{2} 3. Simplify: 2<x3-2 < x \leq 3 Strategic Tip: Whatever you do to the middle, you must do to the left and right sides. Choice B is incorrect because it swaps the strict (<<) and inclusive (\leq) inequalities. Choice C is incorrect because it might result from adding 1 instead of subtracting. Choice D is incorrect because it combines wrong values and wrong signs.

Key Steps:

The correct answer is 2<x3-2 < x \leq 3

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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