7

Set 10: Linear Inequalities (Advanced)

Explanation

Answer: A

Find the minimum value of C=4x+5yC = 4x + 5y in the region with vertices (0,6)(0, 6), (4,2)(4, 2), and (7,0)(7, 0) bounded by x,y0x, y \geq 0.

A.

2626

✓ Correct
B.

3030

C.

2828

D.

00

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Test the vertices. 1. (0, 6): C=4(0)+5(6)=30C = 4(0) + 5(6) = 30 2. (4, 2): C=4(4)+5(2)=16+10=26C = 4(4) + 5(2) = 16 + 10 = 26 3. (7, 0): C=4(7)+5(0)=28C = 4(7) + 5(0) = 28 4. Minimum: 26 is the lowest value. Strategic Tip: Don't assume the vertex closest to the origin is the minimum; coefficients matter. Choice B is incorrect because 30 is the maximum. Choice C is incorrect because 28 is not the minimum. Choice D is incorrect because (0,0)(0,0) is not a vertex of this region.

Key Steps:

The correct answer is 2626

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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