10

Set 8: Linear Functions (Intermediate)

Explanation

Answer: A

A car depreciates linearly. Value new: $20,000. Value after 5 years: $10,000. What is the value after 8 years?

A.

$4,000

✓ Correct
B.

$6,000

C.

$8,000

D.

$2,000

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Find rate and project. 1. Change: 10,000−20,000=−10,00010,000 - 20,000 = -10,000 in 5 years. 2. Rate: −10,000/5=−2,000-10,000 / 5 = -2,000 per year. 3. Model: V=−2000t+20,000V = -2000 t + 20,000. 4. Calculate: t=8t=8. V=−2000(8)+20,000=−16,000+20,000=4,000V = -2000(8) + 20,000 = -16,000 + 20,000 = 4,000. Strategic Tip: Or step by step: Year 5 is 10 k. Year 6 is 8 k. Year 7 is 6 k. Year 8 is 4 k. Choice B is incorrect. Choice C is incorrect. Choice D is incorrect.

Key Steps:

•

The correct answer is $4,000

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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