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Set 17: Exponential Functions (Intermediate)

Explanation

Answer: A

Coffee at 180°F cools in a 70°F room. After 5 minutes it's 150°F. Using Newton's Law T(t)=70+110ektT(t) = 70 + 110e^{-kt}, find kk.

A.

About 0.063

✓ Correct
B.

About 0.1

C.

About 0.05

D.

About 0.15

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Solve for the cooling constant kk. 1. Given: T(5)=150T(5) = 150, so 150=70+110e5k150= 70 + 110 e^{-5 k}. 2. Isolate: 80=110e5k80= 110 e^{-5 k}. 3. Divide: e5k=80110=8110.727e^{-5 k} = \frac{80}{110} = \frac{8}{11} \approx 0.727. 4. Natural log: 5k=ln(0.727)0.318-5 k = \ln(0.727) \approx -0.318. 5. Solve: k=0.31850.0640.063k = \frac{0.318}{5} \approx 0.064 \approx 0.063. Strategic Tip: Use given data points to find unknown constants in exponential models. Choice B is incorrect because this cooling rate is too fast. Choice C is incorrect because this is slightly too slow. Choice D is incorrect because this rate is way too fast.

Key Steps:

The correct answer is About 0.063

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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