10

Set 14: Exponential Functions

Explanation

Answer: A

A quantum computer's qubit count follows Moore's Law variant: Q(t)=10⋅2t/1.5Q(t) = 10 \cdot 2^{t/1.5} where tt is years. How many qubits after 6 years?

A.

160 qubits

✓ Correct
B.

80 qubits

C.

40 qubits

D.

320 qubits

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Evaluate at t=6t = 6. 1. Substitute: Q(6)=10⋅26/1.5=10⋅24Q(6) = 10 \cdot 2^{6/1.5} = 10 \cdot 2^4. 2. Calculate: 24=162^4 = 16. 3. Result: 10×16=16010\times 16 = 160 qubits. Strategic Tip: Doubling every 1.5 years means 4 doublings in 6 years. Choice B is incorrect because this is only 3 doublings. Choice C is incorrect because this is only 2 doublings. Choice D is incorrect because this is 5 doublings.

Key Steps:

•

The correct answer is 160 qubits

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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