5

Set 8: Exponential Functions (Advanced)

Explanation

Answer: A

A superconductor's resistance drops as R(T)=50e0.1TR(T) = 50e^{-0.1T} ohms where TT is temperature in Kelvin. At what temperature is resistance 5 ohms?

A.

About 23 K

✓ Correct
B.

About 30 K

C.

About 15 K

D.

About 40 K

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Solve for TT when R(T)=5R(T) = 5. 1. Equation: 5=50e0.1T5= 50 e^{-0.1 T}. 2. Divide: 0.1=e0.1T0.1= e^{-0.1 T}. 3. Natural log: ln(0.1)=0.1T\ln(0.1) = -0.1 T. 4. Solve: T=ln(0.1)0.1=2.3030.123.0323T = \frac{\ln(0.1)}{-0.1} = \frac{-2.303}{-0.1} \approx 23.03 \approx 23 K. Strategic Tip: ln(0.1)=ln(10)2.303\ln(0.1) = -\ln(10) \approx -2.303. Choice B is incorrect because this is too high. Choice C is incorrect because this is too low. Choice D is incorrect because this is way too high.

Key Steps:

The correct answer is About 23 K

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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