7

Set 14: Exponential Functions (Advanced)

Explanation

Answer: A

A population decays following P(t)=5000(0.92)tP(t) = 5000(0.92)^t where tt is in years. After how many years will the population be half its initial size?

A.

About 8 years

✓ Correct
B.

12 years

C.

4 years

D.

6 years

Detailed Explanation

Choice A is correct. Choice A is the correct answer. Find the half-life. 1. Target: Half of 5000 = 2500. 2. Equation: 2500=5000(0.92)t2500= 5000(0.92)^t, so (0.92)t=0.5(0.92)^t = 0.5. 3. Test: - t=8t=8: (0.92)80.513(0.92)^8 \approx 0.513 (close to 0.5) ✓ - t=9t=9: (0.92)90.472(0.92)^9 \approx 0.472 (below 0.5) 4. Answer: About 8 years. Strategic Tip: For decay factor 0.92, half-life ≈ ln(0.5)ln(0.92)8.3\frac{\ln(0.5)}{\ln(0.92)} \approx 8.3 years. Choice B is incorrect because decay is faster. Choice C is incorrect because (0.92)40.7160.5(0.92)^4 \approx 0.716 \neq 0.5. Choice D is incorrect because (0.92)60.6060.5(0.92)^6 \approx 0.606 \neq 0.5.

Key Steps:

The correct answer is About 8 years

Why others are wrong:
B: Choice B is incorrect and may result from a calculation error.
C: Choice C is incorrect and may result from a calculation error.
D: Choice D is incorrect and may result from a calculation error.

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